Abs
Abs(value)
Additional Notes
Returns a positive integer for a given numerical value, essentially stripping the sign from the number. Abs(-4) returns 4
Abs returns only integers, in effect it works like Abs(Int(SomeValue)).
A workaround is to multiply your number before Abs-ing by a factor big enough to get the precision you need, and then dividing it again at the end vis:
mynum *= 1000
MyNewNum = Abs(mynum)
MyNewNum /= 1000
(BTW If you're unsure what *= and /= means, they're unary operators they mean multiply or divide the number on the left by the number on the right)
I found a subroutine in several of Apple's included effects called fabs(), presumably floating point abs:
on fabs (value _n)
return (_n<0 ? -_n : _n);
end;
Before finding that I wrote my own version:
on absNoInt(value _num)
return _num * sign(_num);
end
I never bothered to test which one was faster, it would depend on whether the ternary conditional (?:) operator was faster than the sign function.
Abs(3.47) would then become 4?
Abs will always return a positive integer based on your input. All values are rounded towards zero then returned as a positive number. So:
Abs(3.47) = 3
Abs(3.999999) = 3
Abs(-3.47) = 3
Hi Joe,
you can use my CommandSpeed-filter I gave you at the NAB to check which one is faster.
But I suspect that there won't be a big (noticable) difference between the two subroutins.
Hi Christoph, now that you've gone and called me out like that I guess I have no choice...
The performance is virutally identical, however my absNoInt() routine is just slightly faster than Apple's fabs(), by maybe 3-5%. Not a big deal, and they're both essentially instant.
